Friday, August 27, 2010
Algebraic problems
Take a glance at the equation below. As you can see, after the variable is subtracted from the left and the constants are subtracted from the right, you are still left with 2x on one side.
Preliminary Equation / Issue x + 23 = 3x + 45
Subtract x from each side x - x + 23 = 3x - x + 45
Result 23 = 2x + 45
Subtract 45 from each side 23 - 45 = 2x + 45 - 45
Result -22 = 2x
2x = -22
more on:
Math world
Factor of 25
Thursday, August 26, 2010
Math problems
Question: A women wants to select one cotton saree and one polyster saree from a collection of 8 cotton sarees and 11 polyster sarees. In how many ways can the lady choose the two sarees?
Answer: Here, there are two events E1 and E2.
E1 = Selection of one cotton saree from 8 cotton sarees.
E2 = Selection of one polyster saree from 11 polyster sarees.
E1 = 8 ways E2 = 11 ways
more help on:
Wednesday, August 25, 2010
Polynomials
Factoring a polynomial:
Factoring a polynomial into irreducible polynomials over a given field. It gives out the factors that form a polynomial function. the function in the form of xn + xn - 1 + xn - 2 +…… + k = 0 here k is a constant and n is a power.
Example: Factoring a polynomial (x + 3)2
x2 + 9x + 6
(x + 3)(x + 3)
more on:sine and tan rules
how to factor polynomial step by step?
Monday, August 23, 2010
Histogram Defination
Histogram is an easy method to represent database.
The following steps used to construct the histogram in definition of histogram tutoring:
Step 1:
here in histogram data ranges are dividing by equal intervals in a column. For example (0 to 5, 5 to 10, and 10 to 15)
Step 2:
We need to create x-axis and y-axis. X-axis represented by horizontal position and y-axis represented by vertical position.
Step 3:
Given data (class intervals) are plot into x-axis (horizontal position).
Step 4:
Given data (frequency) are plot into y-axis (vertical position).
Linesslope coefficient
Saturday, August 21, 2010
8th Grade Algebra
Example Problems for 8th Grade Algebra I:
8th grade algebra i – Example: 1
Solve: 10(q – 8) – 16q - 20 = 3(q + 15)
Solution:
Given expression is
10(q – 8) – 16q - 20 = 3(q + 15)
Multiplying the integer terms
10q - 80 – 16q - 20 = 3q + 45
Grouping the above terms
-6q - 100 = 3q + 45
Add 100 on both sides
-6q + 100 – 100 = 3q + 45 + 100
Grouping the above terms
-6q = 3q +145
Subtract 3q by on both sides
-6q – 3q = 3q +145 – 3q
Grouping the above terms
-9q = 145
Divide -9 on both sides
q = 145/-9
q = (145)/(9)
Answer: q = 145/9.
help related to :adding decimals
Friday, August 13, 2010
free geometry tutoring
Hi Friends!!!
How many of you like doing homework regularly.
Many students face difficulty in doing geometry homework individually.
We can get help from geometry tutor.
many tutors give free geometry tutoring to students who are in need.
geometry tutoring through online made possible to solve students queries related to geometry
1.The circumference of a circle is equal to 46π. Find the radius of the circle.
Sol : The circumference of a circle is given by
C = 2πr
Where r is the radius of the circle.
Substitute C by 46π to obtain the equation
46π = 2πr
Simplify and solve for r to obtain
r =23
Ans : radius of the circle r=23
If you need Free geometry help you can click on given link.
Thursday, August 12, 2010
solved pre algebra problems
let us know solved pre algebra problems
Pre algebra is the basic for mathematics. Pre algebra using letters, general Verification of relations and other symbols to represent specific sets of values, numbers vectors, etc., in the character of such relations. It deals the topics such as numbers, expressions, variables, equations, word problems, polynomials. Let us solve some sample problems on pre algebra.
Some Concepts in Pre algebra :
Concepts of algebra
Terms are the part of expression that is connected with plus and minus signs
Coefficients are the numbers in the terms with variables combined in it.
4x2 + 2y + 8xy + 16
Here Coefficient of x2 is 4
Coefficient of y is 2
Coefficient of xy is 8
In any expressions, x and y are called as variables. We call them as variables because these numbers may vary , one or more numbers for the variables can be assigned for the expression.
In the expression 4x2 -5y2+ 3xy + 6 the variable terms are x2, y2, xy.
In any expression which contains only numbers without variables are called as Constants, because their values never change.
In the expression 2x2 -3y2+ 7xy + 5 the constant term is "5."
One or more terms in certain phrase, is called Algebraic Expression. It includes variables, constants and symbols. Symbols such as plus and minus signs. It's only a phrase, not the whole sentence. So it never include equal sign.
Expression: x2 + 3y + 8xy + 14
Equation consists of expressions that are separated by the equal sign. By using expression on one side and equals with their values on the other side.